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(a-i) (a+i) = 0
a² - i² = 0
a² = i²
|a| = |i|
|i| = √6
a(a-i) = 3
a.a - a.i = 3
|a|² - |a|.|i|.cosα = 3
(√6)² - √6.√6.cosα = 3
6 - 6.cosα = 3
-6.cosα = 3 - 6
-6.cosα = -3
cosα = 1/2
cosα = cos (π/3)
jadi, α = π/3
semoga membantu ya :)