jak się oblicza takie działania POTĘGI
a) (3^5 * 3^7) : 9^4=
b) 2^20 : (4^2 * 8^3)=
poproszę o dokładne rozwiązania.
a) (3^5 * 3^7) : 9^4= 3^(5 + 7) : (3^2)^4 = 3^12 : 3^8 = 3^(12 - 8) = 3^4 = 81
b) 2^20 : (4^2 * 8^3)= 2^20 : [ (2^2)^2 * (2^3)^3) = 2^20 : (2^4 * 2^9) = 2^20 : 2^(4 + 9) = 2^20 : 2^13 = 2^(20 - 13) = 2^7 = 128
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a) (3^5 * 3^7) : 9^4= 3^(5 + 7) : (3^2)^4 = 3^12 : 3^8 = 3^(12 - 8) = 3^4 = 81
b) 2^20 : (4^2 * 8^3)= 2^20 : [ (2^2)^2 * (2^3)^3) = 2^20 : (2^4 * 2^9) = 2^20 : 2^(4 + 9) = 2^20 : 2^13 = 2^(20 - 13) = 2^7 = 128