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reakcja i proporcja:
2 mol 1 mol
2Na2S2O3 + I2 = Na2S4O6 + 2NaI
0.0025 mol x
x = 0.00125 mol
Masa molowa K2Cr2O7 to 294 g/mol, masa naważki to:
K2Cr2O7 + 2KI + H2SO4 → Cr2(SO4)3 + I2 + K2SO4 + H2O
↑6e ↓2e
--------6e------
1 3
294 g 3 mol
K2Cr2O7 + 6KI + 4H2SO4 →Cr2(SO4)3 + 3I2 + K2SO4 + 4H2O
x 0.00125 mol
x = 0.1225 g
proszę :)