Ile atomów tlenu zawiera 150 dm3 CO2 w T=289K p=1000 hPa
150dm3=0,15m3
1000hPa=100000Pa
R=8,31 J/mol*K
pV= nRT
n= pV/RT
n= 100000Pa*0,15m3/8,31*289
n= 15000/2401,59
n= 6,25 mola CO2
1 mol CO2 ------------- 12,04*10^23 atomów O2
6,25 mola CO2-------- X
X=75,25*10^23 atomow O2
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150dm3=0,15m3
1000hPa=100000Pa
R=8,31 J/mol*K
pV= nRT
n= pV/RT
n= 100000Pa*0,15m3/8,31*289
n= 15000/2401,59
n= 6,25 mola CO2
1 mol CO2 ------------- 12,04*10^23 atomów O2
6,25 mola CO2-------- X
X=75,25*10^23 atomow O2