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x-lizcba aut
12-x-motorów
4x+2(12-x)=38
4x+24-2x=38
2x=38-24
2x=14
x=7
12-7=5
5 motocykli stoi na parkingu
(5*2=10
7*4=28
28+10=38
:)
auto: 4 k
2k+4k=6k
38k:6k=6 i zostaje 2k czyli 1 motocykl
6+1=7 motocykli