(k + 1)x² + 2x + 1 = 0
warunki:
Δ > 0 i 1/(k+1) < 0, k+1 ≠ 0
Δ = b²-4ac = 4 - 4(k+1) = 4 - 4k + 4 = -4k
-4k > 0 /:(-4)
k < 0
k+1 < 0
k < -1
Odp. Dla k ∈ (-∞; -1)
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(k + 1)x² + 2x + 1 = 0
warunki:
Δ > 0 i 1/(k+1) < 0, k+1 ≠ 0
Δ = b²-4ac = 4 - 4(k+1) = 4 - 4k + 4 = -4k
-4k > 0 /:(-4)
k < 0
k+1 < 0
k < -1
Odp. Dla k ∈ (-∞; -1)