Wiedząc,że α jest kątem ostrym, oblicz wartość wyrażenia: tgα+ cosα /tgα - cosα (ułamek) gdy tgα = 2.... Question from @lostangel11

August 2018 1 24 Report

Wiedząc,że α jest kątem ostrym, oblicz wartość wyrażenia:

tgα+ cosα /tgα - cosα (ułamek) gdy tgα = 20/21 (ułamek)

Janek191 Tg α = 20/21
tg α = y/x, zatem y = 20, x = 21
r² =x² + y² = 21² + 20² = 441 + 400 = 841
r =√841 = 29
cos α =x/r = 21/29
[ tg α + cos α]/ [tg α - cos α] =[20/21 +21/29]/[20/21 -21/29] =
= [580/609 + 441/609]/[580/609 - 441/609] =
= [1021/609]/[139/609] = [1021/609]*[609/139] = 1021/139≈7,35
/ - kreska ułamkowa

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lostangel11 September 2018 | 0 Replies

jak wygląda reakcja na potwierdzenie, iż NaOH jest higroskopijny?czy istnieje cos takiego NaOH+H2O--> ?

Answer

lostangel11 August 2018 | 0 Replies

Dla jakich wartości parametru k równanie ma dwa różne pierwiastki przeciwnych znaków: (k+1)x^2+2x+1=0

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jak wygląda reakcja na potwierdzenie, iż NaOH jest higroskopijny?czy istnieje cos takiego NaOH+H2O--> ?

Dla jakich wartości parametru k równanie ma dwa różne pierwiastki przeciwnych znaków: (k+1)x^2+2x+1=0

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