Dany jest wielomian . Oblicz
v(-1)=2·(-1)-1+3+1=-2+3=1
v(0)=1
v(√2)=4√2-2-3√2+1=√2-1
v(-1)-3v(0) 1-3 -2(√2+1)
-------------------------- =----------------------- = -------------------- =-2(√2+1)
v(√2) √2-1 (√2-1)(√2+1)
v(-1) = 1
v(0) = 1
v(√2) = √2-1
-2/√2-1 = -2(√2+1) / (√2-1)/(√2+1) = -2(√2+1)
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v(-1)=2·(-1)-1+3+1=-2+3=1
v(0)=1
v(√2)=4√2-2-3√2+1=√2-1
v(-1)-3v(0) 1-3 -2(√2+1)
-------------------------- =----------------------- = -------------------- =-2(√2+1)
v(√2) √2-1 (√2-1)(√2+1)
v(-1) = 1
v(0) = 1
v(√2) = √2-1
-2/√2-1 = -2(√2+1) / (√2-1)/(√2+1) = -2(√2+1)