dany jest ciag okreslony wzorem . wyznacz sume trzech poczatkowych wyrazow ciagu
odp:
48
an=3n+1
b(n)=a(2n+1)=3(2n+1)+1=6n+3+1=6n+4
b₁=6×1+4=10
b₂=6×2+4=16
b₃=6×3+4=22
S₃=10+16+22=48
b₁=6*1+4=10
b₂=6*2+4=16
b₃=6*3+4=22
b₁+b₂+b₃=10+16+22=48
lub
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an=3n+1
b(n)=a(2n+1)=3(2n+1)+1=6n+3+1=6n+4
b₁=6×1+4=10
b₂=6×2+4=16
b₃=6×3+4=22
S₃=10+16+22=48
b₁=6*1+4=10
b₂=6*2+4=16
b₃=6*3+4=22
b₁+b₂+b₃=10+16+22=48
lub