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warunki:
a+3>0 ∧ Δ≤0
ROZWIAZANIE:
Δ=16-8(a+3)=16-8a-24=-8-8a
-8-8a≤0
8a≥-8
a≥-1 ∧ a>-3
ODP a≥-1
Patrz zalacznik dla a=-1 lub a=0
f(x)=2x²- 4x +2
f(x)=3x²- 4x +2