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2a {(a+2)(3a - 1) – [a + 2(a – 1)(a + 3)]} =
2a {3a² - a + 6a - 2 - [a + 2 (a² + 3a - a - 3)]} =
2a {3a² + 5a - 2 - [a + 2a² + 4a - 6]} =
2a {3a² + 5a - 2 - a - 2a² - 4a + 6} =
2a {a² + 4} = 2a³ + 8a
2a · (a² + 4) = 0 → a₁= -2 // a₂= √-4 No tiene solución
2a = 0 → a = -2
a² + 4 = 0 → a² = -4 → a = √-4