a ma wyjsc 2 a mi wychodzi log₂6
log 2 (3) + log 2(12) = log 2(3) + log 2(3*4) = log 2(3) + log2(3) + log2(4) =
= 2 log 2(3) + 2 = 2*( log 2(3) + 1)
log2(30) - log 2(5) = log2(30 : 5) = log 2(6) = log2( 2*3) = log 2(2) + log2(3) = 1 + log2(3)
zatem
a = [ 2*( log 2(3) + 1)]/ [ 1 + log2(3)] = 2
=====================================
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
log 2 (3) + log 2(12) = log 2(3) + log 2(3*4) = log 2(3) + log2(3) + log2(4) =
= 2 log 2(3) + 2 = 2*( log 2(3) + 1)
log2(30) - log 2(5) = log2(30 : 5) = log 2(6) = log2( 2*3) = log 2(2) + log2(3) = 1 + log2(3)
zatem
a = [ 2*( log 2(3) + 1)]/ [ 1 + log2(3)] = 2
=====================================