Zad. Zapisz w postaci jednej potęgi
a) 4⁵/2⁷× 5³
b) 9³×4⁴/ 6¹⁰
a) 4⁵/2⁷× 5³=
=( 2²)⁵/2⁷* 5³=
= 2¹⁰: 2⁷* 5³=
= 2³ *5³=
= (2*5)³=
= 10³
= ( 3²)³ * (2²)³: 6¹⁰=
= 3⁶*2⁶ : 6¹⁰ =
= ( 6)⁶ : 6¹⁰ =
= 6^(-4)=
= (1/6)⁴
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Zad. Zapisz w postaci jednej potęgi
a) 4⁵/2⁷× 5³=
=( 2²)⁵/2⁷* 5³=
= 2¹⁰: 2⁷* 5³=
= 2³ *5³=
= (2*5)³=
= 10³
b) 9³×4⁴/ 6¹⁰
= ( 3²)³ * (2²)³: 6¹⁰=
= 3⁶*2⁶ : 6¹⁰ =
= ( 6)⁶ : 6¹⁰ =
= 6^(-4)=
= (1/6)⁴