Question

(log√⁷ 6+log√⁷ 1/42)(log½ 1⅛-log½ 9)

Pomóżcie !! Pilne

Answer 1

(log√⁷ 6+log√⁷  1/42)(log½ 1⅛-log½ 9) =

 

(log√⁷ (6 *  1/42)(log½ (1⅛ : 9) = (log√⁷ (1/7)(log½ (9/8 * 1/9) =

 

(log√⁷ (√7)^(-2) (log½ (1/8) = -2 *  (log√⁷ (√7) (log½ (1/2)³  = -2 * 1 * 3 * 1 = - 6

Answer 2

    (log_√7 6 + log_√7 1/42)(log_½ 1⅛ - log_½ 9) =

 

= [log_√7(6 * 1/42)]*[log_½(9/8 : 9)] =

 

= [log_√7(1/7)]*[log_½(1/8)] =

 

= (log_√7 √7⁻²)*[log_½ (1/2)³] = 

 

= -2 *3 =

 

= -6