oblicz
√³2 i 10/27 - (3/4)⁻¹: (`1,2)²
∛2 10/27 - (3/4)⁻¹ : (1,2)² = ∛64/27 - 4/3 : 1,44 = 4/3 - 4/3 : 144/100 =
= 4/3 - 4/3 * 100/144 = 4/3 - 4/3 * 25/36 = 4/3 - 25/27 = 36/27 - 25/27 =
= 11/27
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∛2 10/27 - (3/4)⁻¹ : (1,2)² = ∛64/27 - 4/3 : 1,44 = 4/3 - 4/3 : 144/100 =
= 4/3 - 4/3 * 100/144 = 4/3 - 4/3 * 25/36 = 4/3 - 25/27 = 36/27 - 25/27 =
= 11/27