Skróć ułamki. Podaj konieczne założenia.
a) a(a+2)/2a
c)ab+3b / a+3'
a) x(x+2)-3(x+2)/x-3
'c) (x+1)x+(x+1) / (x+1) do kwadratu
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a) a≠0
a(a+2)/2a =(a+2)/2
b) a≠-3
ab+3b/a+3 = b(a+3)/(a+3)=b
c) a≠3
x(x+2)-3(x+2)/x-3 = (x-3)(x+2)/x-3 =x+2
d)x≠-1
(x+1)x+(x+1)/(x+1)^2 = x(x+1)+(x+1)/(x+1)^2=
=(x+1)(x+1)/(x+1)^2 =(x+1)^2/(x+1)^2 = 1