Prosze o pomoc .Rozwiąż równanie 1/9x2 -1/4 =0 mam podstawić to do wzoru ∆=b2-4ac ???
1/9x²-1/4=0
a=1/9
b=0
c=-1/4
Δ=0²-4*1/9*(-1/4) = 1/9
√Δ=⅓
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1/9x²-1/4=0
a=1/9
b=0
c=-1/4
Δ=0²-4*1/9*(-1/4) = 1/9
√Δ=⅓