Question

Nilai Limit ➡ 3 x - √2x + 3 / x² - 9 =
A. 1/3
B. 1/9
C. 0
D. - 1/3
E. 3​

Answer 1

pake dalil l'hopital..

lim x--> 3

1 - (1/2(2x+3)^-1/2.2) / 2x

Lim x--> 3

1 - (2x+3)^(-1/2) / 2x

Lim x--> 3

1 - (1/√(2x+3) / 2x

masukkin x = 3, jadi

1 - (1/√(2.3+3) / 2(3) =

1- (1/√9) / 6 =

1- (1/3) / 6 =

(2/3) / 6 =

(2/3)*(1/6) =

2/18 =

1/9

Answer 2

Jawaban:

menggunakan dalil L'hospital

Penjelasan dengan langkah-langkah:

dilampirkan pada gambar