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ax+bx-abx=-a/2b+b/2a+2ab/2 /*2ab
x(a+b-ab)*2ab=-a+bb+2 /:[(a+b-ab)*2ab]
x=[-a+bb+2]/[(a+b-ab)*2ab]
2) a/c-x + c/a-x = a+c/b-c
-2x=a+c/b-c-a/c-c/a /(-2)
x=[a+c/b-c-a/c-c/a ]/2
3) x/b(a-x) + c/d(x-a) = ad-bc/3abd
x/b(a-x) + c/d(-1)(-x+a) = ad-bc/3abd /bd
xd(a-x)-cb(a-x)=add-bbbcd/3
xda-xxd-cba+cbx=add-bbbcd/3
-x^2*d+x(da+cb)=add-bbbcd/3+cba
-x^2*d+x(da+cb)-add+bbbcd/3-cba=0
teraz oblicz delte i x1 i x2
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