August 2018 1 26 Report
(3√5²) =
(2√2+1)²=
(2x-3) (2x+3)=
(⁵√3+1)³=
(x-2y)³=
(y+4) (16-4y+y²)=
√242-√300 +√338 - √48=

i ułamek na górze w liczniku jest 6 - 3√2
na dole w mianowniku 3 i drugi ulamek
w liczniku 2√10 - 2√2 w mianowniku 2√2 i od tego ulamka odjac √5 (czyli - √5)
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