Jawaban:
-24
Penjelasan dengan langkah-langkah:
x^3 - 3x² + 4x + 5 = 0
a = 1; b = -3; c = 4; d = 5
(x1)^3 + (x2)^3 + (x3)^3
= (x1 + x2 + x3)^3 - 3 . (x1 + x2 + x3) . (x1 . x2 + x1 . x3 + x2 . x3) + 3 . (x1 . x2 . x3)
= (-b/a)^3 - 3 . (-b/a) . c/a + 3 . (-d/a)
= (-(-3/1))^3 - 3 . (-(-3/1)) . 4/1 + 3 . (-5/1)
= 27 - 3 . 3 . 4 + 3 . (-15)
= 27 - 36 - 15
= -24
Kode Kategorisasi : 11.2.4
Kelas 11
Pelajaran Matematika
Bab 4 - Suku Banyak
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Jawaban:
-24
Penjelasan dengan langkah-langkah:
x^3 - 3x² + 4x + 5 = 0
a = 1; b = -3; c = 4; d = 5
(x1)^3 + (x2)^3 + (x3)^3
= (x1 + x2 + x3)^3 - 3 . (x1 + x2 + x3) . (x1 . x2 + x1 . x3 + x2 . x3) + 3 . (x1 . x2 . x3)
= (-b/a)^3 - 3 . (-b/a) . c/a + 3 . (-d/a)
= (-(-3/1))^3 - 3 . (-(-3/1)) . 4/1 + 3 . (-5/1)
= 27 - 3 . 3 . 4 + 3 . (-15)
= 27 - 36 - 15
= -24
Kode Kategorisasi : 11.2.4
Kelas 11
Pelajaran Matematika
Bab 4 - Suku Banyak