September 2018 1 47 Report

rozwiaz rownanie:

sin(x+\frac{\pi}{6})=\frac{\sqrt3}{2}sinx-\frac{1}{4}\ dla \ x\in(-2\pi,2\pi).

odp:

x∈{-4/3π,-2/3π,2/3π,4/3π}

dokladne obliczenia


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