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w a) ma wyjść 1/( log_6 10).

W b) powinno wyjść (25√6)/6,

W c) powinno być 2 i 2/3

a) log96 ^(0,25) - 1/4log 2/27

b) 36^ ( log_6 5 - \frac{1}{4} )

c) 27^ ( log_3 2 - \frac{1}{3} )


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