Question

7.6

b) √-2³√-8=

c)⁷√-⁶√-⁵√-1=

b)∛1 13/27,⁴√0,0048 , ∛-1 34/216/ ⁵√ -243/256=

zad 2

2) (4√2+1)³=

3)(4√2-1)²-(√2+1)³=

Answer 1

7.6

b) √-2³√-8=

= nie wiem czy to ∛ czy (-2)² - pisz dokładnie!

 

c)⁷√-⁶√-⁵√-1=

= ⁷√-⁶√[-(1)] =

= ⁷√-⁶√1 =

= ⁷√-1 =

= -1

 

b)∛1 13/27,⁴=

= ∛(40/27)³*∛(40/27) =

= (49/27)*∛(8*5)/27 =

= (49/27)*∛8*∛5 /∛27 =

= (49/27)*2*∛5/ 3 =

=(49/17)*3*2*∛5 =

= (98/9)*∛5

 

√0,0048 =

= √(48/10000 ) =

= √16*√3 / √10000 =

= 4*√3 /100 =

= (4/100)*√3 =

= 0,04*√3

 

∛-1 34/216/ ⁵√ -243/256=

= ∛(-250/216) / ⁵√(-243/256)=

= [ - ∛5³*∛2/ ∛6³] : [ -⁵√3⁵/ ⁵√2⁸ =

 

 - (∛5 )³*∛2      ⁵√2⁸      5*∛2 (⁵√*2⁸)*(⁵√2)³     5*∛2* 2*⁵√8     10*∛2*⁵√8

=----------- * ----------- =  ------------------------ = ---------------  =   ----------- =

     ∛6³        - ⁵√3⁵                6*3                          18                     18

 

= (5/9)*∛2 *⁵√8

 

 

zad 2

 

2) (4√2+1)³=

= (4√2)³ +3*(4√2)²*1 + 3*4√2*1¹ + 1=

= 64*2*√2 + 3*16*2 + 12*√2 =

= 128√2 + 12√2 + 96 =

= 140√2 +96 =

= 4(35√2 + 24)

 

3)(4√2-1)²-(√2+1)³=

= (4√2)² -2*4√2*1 +1 -[ ( √2)³ +3*(√2)²*1 + 3*√2*1² +1³) =

= 16*2 - 8√2 + 1 -2√2 -6 -3√2 -1  =

= -13√2  + 26 =

= 13( 2 -√2)