Jeśli liczba sinx + cosx = (pierwiastek z 5)/2 to liczba (sinx - cosx)^2 wynosi: ?
(sinx+cosx)²=(√5/2)²
sin²x+2sinxcosx+cos²x=5/4
2sinxcosx=5/4-1=1/4
(sinx-cosx)²=1-2sinxcosx=1-1/4=3/4
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(sinx+cosx)²=(√5/2)²
sin²x+2sinxcosx+cos²x=5/4
2sinxcosx=5/4-1=1/4
(sinx-cosx)²=1-2sinxcosx=1-1/4=3/4