zad.1
SrO-->tlenek strontu
K₂O-->tlenek potasu
SeO₃-->tlenek selenu(VI)
Cl₂O₇-->tlenek chloru(VII)
zad.2
mFe₂O₃=2*56g+3*16g=160g
%Fe=112g/160g * 100%
%Fe=70%
Zadanie 1
SrO - tlenek strontu
K₂0 - tlenek potasu
SeO₃ - tlenek selenu (VI)
Cl₂O₇ - tlenek chloru (VII)
Zadanie 2
tlenek żelaza (III) - Fe₂O₃
m Fe₂O₃ = 2*56u+3*16u = 112u+48u = 160u
(2*56u)/160u *100% = 112u/160u*100% = 7/10*100% = 70%
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zad.1
SrO-->tlenek strontu
K₂O-->tlenek potasu
SeO₃-->tlenek selenu(VI)
Cl₂O₇-->tlenek chloru(VII)
zad.2
mFe₂O₃=2*56g+3*16g=160g
%Fe=112g/160g * 100%
%Fe=70%
Zadanie 1
SrO - tlenek strontu
K₂0 - tlenek potasu
SeO₃ - tlenek selenu (VI)
Cl₂O₇ - tlenek chloru (VII)
Zadanie 2
tlenek żelaza (III) - Fe₂O₃
m Fe₂O₃ = 2*56u+3*16u = 112u+48u = 160u
(2*56u)/160u *100% = 112u/160u*100% = 7/10*100% = 70%