September 2018 1 54 Report

rozwiaz uklad rownan dla x∈<0,2π>; y∈<0,2π>:

\left \{ {{sin(x+y)=-\frac{1}{2}} \atop {y-2x=\frac{\pi}{6}}} \right

odp:

x=π/3 i y=5/6π

lub

x=5/9π i y=23/18π


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