Question

Matematyka z plusem 2 strona 90 zadanie 8 i 9

z8.

a) (2a+b)*c-(2ac-bc+1)=

b)5(x-z)+2(z-x)=

c)2x^(2) (x-5)-3x(x^(2)-3x+5)

d)6(a^(2)+b+1/3)-6(a^(2) - 1/2) - 3(b+1/3)=

z9.

a) 6x-12y/3+x-4y =

b)15a+20b/5-3k-9/6=

c)7k+21/14-3k-9/6 =

d)4*3p+6/12+10-5p/15*9=

Answer 1

z8

a) (2a+b)*c-(2ac-bc+1)=2ac+bc-2ac+bc-1=2bc-1

b)5(x-z)+2(z-x)=5x-5z+2z-2x=3x-3z

c)2x^(2) (x-5)-3x(x^(2)-3x+5)=2x³-10x²-3x³+9x²-15x=-x³-x²-15x 

d)6(a^(2)+b+1/3)-6(a^(2) - 1/2) - 3(b+1/3)=6a²+6b+2-6a²+3-3b-1=3b+4

 

z9

a) 6x-12y/3+x-4y =6x-4y+x-4y=7x-8y

b)15a+20b/5-3k-9/6=15a+4b-3k-1,5

c)7k+21/14-3k-9/6 =7k+1,5-3k-1,5=4k

d)4*3p+6/12+10-5p/15*9=12p+0,5+10-3p=9p+10,5