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b)1³-y³
c)2t³-3y³
d)∛1/126-x³ lub gdy by bylo 125 to (1/5)³-x³
b) 1-y⁶ = ( 1-y kw) do 3
c) 8t⁶-27y³ = (2t kw - 3y) do 3
d) 1/126 - x³ = ( pierw. 3 stopnia z 1/126 -x) do 3
a jak mial byc ulamek 1/125 wtedy bedzie tak:
(1/5 - x) do 3
do 3 - znaczy do potegi 3 , a kw - znaczy do kwadratu <do potegi 2>
mam nadzieje ze pomoglam :)