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lb. moli - obj.
0,4 mola - x
2 mole - 22,4 dm3
x=22,4*0,4/:2
x=4,48 dm3
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CH4 + 2O2 -> CO2 + 2H2O
2 moli O2 -----------1 mol Co2
0,4 moli ---------x
x=0,2 mole CO2
V=n*V0
V= 0,2 mole *22,4 dm³/mol=4,48 dm³
CH4 + 2 O2 = CO2 + 2H2O
2mole-----------------22,4dm3
0,4 mola--------------- x
--------------------------------------
x = 0,4mola*22,4dm3/2mole = 4,48 dm3 CO2