Question

znajdz x

a) logx= log8 - log5 + log10

b)log3 x= 3log3 2 + 2 log3 3

c)log5 x = 2log5 3 - ½log5 16 + ⅔ log5 8

d)log4 x= 3 log4 5 - ⅔ log4 4 + ⅓ log4 2

e)log3 x= log3 15 - ⅓ log3 27 - 2 log3 5 + log3 50

f)log2 x= log√2 2 - ½ log3 4 + log3 6 + log3 3

dzieki ;)

Answer 1

a) logx=log8-log5+log10 /:log

x=8-5+10

x=13

b)log3x=3log3*2+2log3*3 /:log3

x=3*2+3

x=9

c)log5x=2log5*3-1/2log5*16+2/3log5*8 /:log5

x=2*3-1/2*16+2/3*8

x=6-8+5 1/3

x=-3 1/3

x= -1

d)log4x=3log4*5-2/3log4*4+1/3log4*2 /:log4

x=3*5-2 2/3+2/3

x=15-2 2/3+2/3

x=13*1 1/3

e)log3x=log3*15-1/3log3*27-2log3*5+log3*50 /:log3

x=15-9-10*50

x= -4*50

x= -200

f)log2x=log√2*2-1/2log3*4+log3*6+log3*3 /:log

2x=√2*2-6+18+9

2x=2-6+18+9

2x=23/:2

x=11,5