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b₁+b₂=⅓
b₁-b₂=1⅔.
b₂/b₁=q
Wyliczamy b₁ np z drugiego równania
b₁+b₂=⅓
b₁=1⅔+b₂
b₂/b₁=q
1⅔+b₂+b₂=⅓
2b₂=-(4/3)
b₂=-⅔
b₁=1⅔-⅔=1
q=-⅔/1=-⅔