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10³√-12
- ________ - 4(³√12 - 5) = -5³√-12 - 4³√12 + 20 = 5³√12 - 4³√12 + 20 = ³√12 + 20
2
√3^3 - 1/5√75 + 2√48 = √27 - 1/5√25*3 + 2√16*3 = √9*3 - √3 + 8√3 = 3√3 - √3 + 8√3 = 10√3
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10³√-12
- ________ - 4(³√12 - 5) = -5³√-12 - 4³√12 + 20 = 5³√12 - 4³√12 + 20 = ³√12 + 20
2
√3^3 - 1/5√75 + 2√48 = √27 - 1/5√25*3 + 2√16*3 = √9*3 - √3 + 8√3 = 3√3 - √3 + 8√3 = 10√3