Question

zapisz w postaci kanonicznej

x2-8x+6

y=x2+4x+8

y=x2-6x-2

y=x2-3x+1

Answer 1

1)y=(x+4)²-20
 2)y=(x+2)²-4
3)y=(x-3)²-11
4)y=(x-1,5)²-1,25

 

Answer 2

postać kanoniczna y=a(x-p)²+q

y= x2-8x+6
a=2, b=-8, c=6
p=⁻b/2a

p= -(-8)/2*2
p=8/4
p= 2
Δ=b²-4ac
Δ=(-8)²-4*2*6
Δ=64-48

Δ=16

q=-Δ/4a
q=-16/4*2

q=-16/8

q=2
y=2(x-2)²+2

 

y=x2+4x+8
a=1, b=4, c=8.
p=⁻b/2a
p=-4/2
p=-2
Δ=b²-4ac
Δ=4²-4*1*8
Δ=16-32= -16

q=-Δ/4a
q=-(-16)/4
q=16/4=4
y=1(x+2)²+4

y=x2-6x-2
a=1, b=-6, c=-2
p=⁻b/2a
p=6/2
p=3
Δ=b²-4ac
Δ=(-6)²-4*1*(-2)
Δ=36+8
Δ=44
q=-Δ/4a
q=-44/4
q=-11
y=1(x-3)²-11

y=x2-3x+1
a=1, b=-3, c=1
p=⁻b/2a
p=3/2
p=1½
Δ=b²-4ac
Δ=(-3)²-4*1*1
Δ=9-4
Δ=5
q=-Δ/4a
q=-5/4
q=-1¼
y=1(x-1½)²-1¼