Zad.1 Rozwiąż równanie;
a) (x-3)do kwadratu= (2x-1)(x-3)
b)x do kwadratu+4x-21=0
a) (x-3)²= (2x-1)(x-3)
x²-6x+9=2x²-6x-x+3
-x²+x+6=0
Δ=1-4*(-1)+6=1+24=25
√Δ=5
x1=-1-5/-2=-6/-2=3
x2=-1+5/-2=4/-2=-2
b)x²+4x-21=0
Δ=16-4*1*(-21)=16+84=100
√Δ=10
x1=-4-10/2=-14/2=-7
x2=-4+10/2=6/2=3
Witaj :)
Rozwiązanie:
a) (x-3)^2 = (2x-1)(x-3)
x^2 - 6x + 9 = 2x^2 - 6x - x + 3
x^2 - x- 6 = 0
Δ = 1 + 24 = 25
pierΔ = 5
x1 = -2
x2 = 3
b) x^2 + 4x - 21 = 0
Δ = 16 + 84 = 100
pierwΔ = 10
x1 =-7
x2 =3
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a) (x-3)²= (2x-1)(x-3)
x²-6x+9=2x²-6x-x+3
-x²+x+6=0
Δ=1-4*(-1)+6=1+24=25
√Δ=5
x1=-1-5/-2=-6/-2=3
x2=-1+5/-2=4/-2=-2
b)x²+4x-21=0
Δ=16-4*1*(-21)=16+84=100
√Δ=10
x1=-4-10/2=-14/2=-7
x2=-4+10/2=6/2=3
Witaj :)
Rozwiązanie:
a) (x-3)^2 = (2x-1)(x-3)
x^2 - 6x + 9 = 2x^2 - 6x - x + 3
x^2 - x- 6 = 0
Δ = 1 + 24 = 25
pierΔ = 5
x1 = -2
x2 = 3
b) x^2 + 4x - 21 = 0
Δ = 16 + 84 = 100
pierwΔ = 10
x1 =-7
x2 =3