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B = (-3;1)
1=a*(-3)-5
1=-3a-5
3a=-6 /:
a=-2
y=ax-5
b=-5
a=?
dane są x i y
B=(-3,1)
x=-3
y=1
zatem podstawiamy do wzoru
y=ax+b
y=ax-5
1=a*(-3)-5
1=-3a-5
-3a-5=1
-3a=1+5
-3a=6/-3
a=-2