Z kwadratu o boku a wycieto jego naroze (zalacznik) Zapisz w jak najprostszej postaci pole powstalego pieciokata
pole kwadartu P1=a²
pole Δ prostokatnego=P2 o bokach : x= a-b i y=a-2b
P=P1-P2=a² -½xy
podstawiamy dane :
P=a²-½(a-b)(a-2b)=a²-½(a² -ab-2ab+2b²)=a²-½(a²-3ab+2b²)=a²-½a²+1½ab-b²=
½a²+1½ab -b²
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pole kwadartu P1=a²
pole Δ prostokatnego=P2 o bokach : x= a-b i y=a-2b
P=P1-P2=a² -½xy
podstawiamy dane :
P=a²-½(a-b)(a-2b)=a²-½(a² -ab-2ab+2b²)=a²-½(a²-3ab+2b²)=a²-½a²+1½ab-b²=
½a²+1½ab -b²