Y=2x-1
Środek okręgu (3,0) znajdź promień r .
s=(3,0)
(x-a)²+(y-b)²=r²
(x-3)²+(y-o)²=r²
(x-3)²+(2x-1)²=r²
x²-2x(-3)+3²+2x²-2*2x*(-1)+(-1)²=r²
x²+6x+9+2x²+4x+1=r²
3x²+10x+10=r²
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s=(3,0)
(x-a)²+(y-b)²=r²
(x-3)²+(y-o)²=r²
(x-3)²+(2x-1)²=r²
x²-2x(-3)+3²+2x²-2*2x*(-1)+(-1)²=r²
x²+6x+9+2x²+4x+1=r²
3x²+10x+10=r²