x = √5-3, y = 2√5+1
x-y = √5-3-(2√5+1) = √5-3-2√5-1 = -4-√5
x/y = (√5-3)/(2√5+1) ·(2√5-1)/(2√5-1) = (√5-3)(2√5-1)/(20-1) = (10-√5-6√5+3)/19 =
= (13-7√5)/19
x² = (√5-3)² = (√5)² -2·3√5 + 3² = 5-6√5+9 = 14-6√5
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
x = √5-3, y = 2√5+1
x-y = √5-3-(2√5+1) = √5-3-2√5-1 = -4-√5
x/y = (√5-3)/(2√5+1) ·(2√5-1)/(2√5-1) = (√5-3)(2√5-1)/(20-1) = (10-√5-6√5+3)/19 =
= (13-7√5)/19
x² = (√5-3)² = (√5)² -2·3√5 + 3² = 5-6√5+9 = 14-6√5