Jest podany wzór funkcji
ƒ(x)= 3/x
]Jaki jest wzór funkcji g(x) jeśli
g(x)= ƒ(x-2)-1
f(x)=3/x
f(x-2)=3/(x-2)
g(x)=f(x-2) - 1
g(x)=3/(x-2) -1
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f(x)=3/x
f(x-2)=3/(x-2)
g(x)=f(x-2) - 1
g(x)=3/(x-2) -1