X6-9x3+8=0 proszę o rozwiązanie Pilne
X6-9x3+8=0
(x³)² - 9x³ + 8 = 0
x³ = t
t² - 9t + 8 = 0
Δ = 81 - 32 = 49
√Δ = 7
t1 = (9 - 7)/2 = 2/2 = 1
t2 = (9 + 70/2 = 16/2 = 8
x³ = 1 lub x³ = 8
x³ = 1³ lub x³ = 2³
x = 1 lub x = 2
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X6-9x3+8=0
(x³)² - 9x³ + 8 = 0
x³ = t
t² - 9t + 8 = 0
Δ = 81 - 32 = 49
√Δ = 7
t1 = (9 - 7)/2 = 2/2 = 1
t2 = (9 + 70/2 = 16/2 = 8
x³ = 1 lub x³ = 8
x³ = 1³ lub x³ = 2³
x = 1 lub x = 2