Question

dana jest funkcja f(x)= x do potęgi 2 +1/x oblicz

a) f(1)

b) f(-3)

c) f(a)

Answer 1

I.Jeżeli:

f(x) = (x²+1)/x

Z: x ≠ 0

a)

f(1) = (1²+1)/1 = 2

b)

f(-3) = [(-3)²+1]/(-3) = (9+1)/(-3) = -10/3 = -3⅓

c)

f(a) = (a²+1)/a = a + 1/a

 

II. Jeżeli:

f(x) = x² + 1/x

a)

f(1) = 1² +1/1 = 1+1 = 2

b)

f(-3) = (-3)² + 1/-3) = 9 - 1/3 = 27/3 - 1/3 = 26/3 = 8⅔

c)

f(a) = a² + 1/a

Answer 2

a)

f(x)=x²+1/x

f(1)=1²+1/1

f(1)=1+1

f(1)=2

 

b)

f(x)=x²+1/x

f(-3)=(-3)²+1/(-3)

f(-3)=9-1/3

f(-3)=27/3-1/3

f(-3)=26/3

f(-3)=8 całych i 2/3

 

c)

f(x)=x²+1/x

f(a)=a²+1/a