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7500 + 7x² - 420x=0
7x² - 420x + 7500=0
a= 7 ; b= -420 ; c= 7500
biaya minimum= -D/4a
= -(b²-4ac)/4a
= -((-420)²-4.7.7500)/4.7
= -(176400-210000)/28
= -(-33600)/28
= 33600/28
= 1200 juta rupiah
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