Question

Nilai dari ³log 81 + ²log 1/32 - 5 log 5√5 =

Answer 1

³log 81 + ²log 1/32 - ⁵log 5√5
= ³log 3⁴ + ²log 2⁻⁵ - (⁵log 5¹ + ⁵log √5)
= 3 ³log 3 -5 ²log 2 - 1 ⁵log 5 - 1/2 ⁵log 5
= 3 - 5 - 1 - 1/2
= -2 - 1 - 1/2
= -3 - 1/2
= -6/2 - 1/2
= -7/2

Answer 2

Bab Logaritma
Matematika SMA Kelas X

3log 81 + 2log (1/32) - 5log 5akar5
= 3log 3^4 + 2log 2^-5 - 5log 5^(3/2)
= 4 - 5 - 3/2
= - 1 - 1 1/2
= - 2 1/2