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x+3=x(x-1)
x+3=x²-x /-x, -3
x² -2x -3=0
Δ= 4-4·1·(-3)= 4+12=16, √16=4
x₁=(2-4):2=-2: 2=-1
x₂=(2+4):2=6:2=3
Odp. Równanie ma dwa rozwiązania: x₁=-1 lub x₂=3.