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a) x1 = (0;0)
y = a(x−p)² + q
y=a(x−1)²+2
0=a(0−1)²+2
-a = 2 | :(-1)
a = -2
f(x) =−2(x−1)² + 2
b) A (3;4)
y = a(x−p)² + q
y = a(x−1)²+2
4 = a(3−1)²+2
4 = 4a + 2
-4a = 2-4
-4a = -2 | :(-4)
a = 0,5
f(x) =0,5(x−1)² + 2