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(x-1)² +0²=5
x²-2x+1=5
x²-2x-4=0
Δ=4+16=20, √Δ=2√5
x1=1-√5 x2=1+√5
Odp (1-√5;0) ; (1+√5;0)
Lub
(x-1)²=5/√
|x-1|=√5 ⇔x-1=√5 ∨x-1=-√5
x=1+√5 ∨x=1-√5