Wyznacz wartosc funkcji f(x)=-x²-4x+1 dla x=3√2 -2
f(x)=-x²-4x+1
f(3√2-2)=-(3√2-2)²-4(3√2-2)+1=-(18+4-12√2)-12√2+8+1=12√2-22-12√2+9=-13
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f(x)=-x²-4x+1
f(3√2-2)=-(3√2-2)²-4(3√2-2)+1=-(18+4-12√2)-12√2+8+1=12√2-22-12√2+9=-13