Wyznacz pierwiastki wielomianu a)f(X)=2x^3-z^2-18z+9
chyba tak powinno być:
f(x)=2x³-x²-18x+9
2x³-x²-18x+9=0
x²(2x-1)-9(2x-1)=0
(2x-1)(x²-9)=0
(2x-1)(x-3)(x+3)=0
x=½ ∨ x=3 ∨ x=-3
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chyba tak powinno być:
f(x)=2x³-x²-18x+9
2x³-x²-18x+9=0
x²(2x-1)-9(2x-1)=0
(2x-1)(x²-9)=0
(2x-1)(x-3)(x+3)=0
x=½ ∨ x=3 ∨ x=-3
licze na naj