Question

Wykonaj:

Answer 1

     x²+y²      x+y                 x²+y²              x+y  

   ---------  - -------  + 1 = -------------   -    ---------  + 1 =

     x²-y²      2x-2y            (x-y)(x+y)          2(x-y)

 

          2(x²+y²) - (x+y)² + 2(x-y)(x+y)       2x²+2y² -(x²+2xy+y²) +2(x²-y²)

    =  --------------------------------------- = ---------------------------------------  =

                 2(x-y)(x+y)                                       2(x²-y²)

 

        2x²+2y²-x²-2xy -y² +2x²-2y²          3x² -y² -2xy

   =  ------------------------------------  = --------------------

                  2(x²-y²)                               2(x²-y²)

     Założenia:

            x-y ≠ 0    ⇒   x ≠ y

            x+y ≠ 0    ⇒   x ≠ -y